2r^2+2r-10=2

Solution for 2r^2+2r-10=2 equation:

Simplifying
2r2 + 2r + -10 = 2

Reorder the terms:
-10 + 2r + 2r2 = 2

Solving
-10 + 2r + 2r2 = 2

Solving for variable 'r'.

Reorder the terms:
-10 + -2 + 2r + 2r2 = 2 + -2

Combine like terms: -10 + -2 = -12
-12 + 2r + 2r2 = 2 + -2

Combine like terms: 2 + -2 = 0
-12 + 2r + 2r2 = 0

Factor out the Greatest Common Factor (GCF), '2'.
2(-6 + r + r2) = 0

Factor a trinomial.
2((-3 + -1r)(2 + -1r)) = 0

Ignore the factor 2.
Subproblem 1
Set the factor '(-3 + -1r)' equal to zero and attempt to solve:

Simplifying
-3 + -1r = 0

Solving
-3 + -1r = 0

Move all terms containing r to the left, all other terms to the right.

Add '3' to each side of the equation.
-3 + 3 + -1r = 0 + 3

Combine like terms: -3 + 3 = 0
0 + -1r = 0 + 3
-1r = 0 + 3

Combine like terms: 0 + 3 = 3
-1r = 3

Divide each side by '-1'.
r = -3

Simplifying
r = -3
Subproblem 2
Set the factor '(2 + -1r)' equal to zero and attempt to solve:

Simplifying
2 + -1r = 0

Solving
2 + -1r = 0

Move all terms containing r to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + -1r = 0 + -2

Combine like terms: 2 + -2 = 0
0 + -1r = 0 + -2
-1r = 0 + -2

Combine like terms: 0 + -2 = -2
-1r = -2

Divide each side by '-1'.
r = 2

Simplifying
r = 2
Solution
r = {-3, 2}